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6a^2=-96+60a
We move all terms to the left:
6a^2-(-96+60a)=0
We add all the numbers together, and all the variables
6a^2-(60a-96)=0
We get rid of parentheses
6a^2-60a+96=0
a = 6; b = -60; c = +96;
Δ = b2-4ac
Δ = -602-4·6·96
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-36}{2*6}=\frac{24}{12} =2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+36}{2*6}=\frac{96}{12} =8 $
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